document.write( "Question 535678: Verify the reduction formula:
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document.write( "a) sin(x - 5pi/2)= -cosx\r
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document.write( "b) sin(x+ pi)= -sinx \n" );
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Algebra.Com's Answer #351995 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Verify the reduction formula: \n" ); document.write( "a) sin(x - 5pi/2)= -cosx \n" ); document.write( "use sin addition formula \n" ); document.write( "sin(s-t)=sin s cos t-cos s sin t \n" ); document.write( "sin(x-5π/2)=sinxcos5π/2-sin5π/2cosx \n" ); document.write( "reference angle for 5π/2=π/2 \n" ); document.write( "cos(5π/2)=cos(π/2)=0 \n" ); document.write( "sin(5π/2)=sin(π/2)=1 \n" ); document.write( "sin(x-5π/2)=sinxcos5π/2-sin5π/2cosx \n" ); document.write( "sin(x-5π/2)=0-cosx=-cosx \n" ); document.write( ".. \n" ); document.write( "b) sin(x+ pi)= -sinx \n" ); document.write( "sin(s+t)=sin s cos t+cos s sin t \n" ); document.write( "sin(x+π)=sinxcosπ+cosxsinπ \n" ); document.write( "cos(π)=-1 \n" ); document.write( "sin(π)=0 \n" ); document.write( "sin(x+π)=sinx*(-1)+cosx*0 \n" ); document.write( "sin(x+π)=-sinx \n" ); document.write( "verified: left side=right side \n" ); document.write( " |