document.write( "Question 52766This question is from textbook
\n" ); document.write( ": A child has 40 coins worth more than $6.00. If the cois are dimes and quarters only, what can you conclude about the number of quarters? \r
\n" ); document.write( "\n" ); document.write( "I can set up a problem with .10x + .25y > 6.00 but this does not address the 40 coins, so I know something is wrong. It doesn't seem like 40-.10x+.25y > 6.00 works either.
\n" ); document.write( "Thanks \n" ); document.write( "
Algebra.Com's Answer #35199 by ankor@dixie-net.com(22740)\"\" \"About 
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A child has 40 coins worth more than $6.00. If the coins are dimes and quarters only, what can you conclude about the number of quarters?
\n" ); document.write( ":
\n" ); document.write( "We can make two equations:
\n" ); document.write( ":
\n" ); document.write( "\"child has 40 coins (dimes & quarters)
\n" ); document.write( "d + q = 40
\n" ); document.write( "and they are worth over $6
\n" ); document.write( ".10d + .25q > 6
\n" ); document.write( ":
\n" ); document.write( "Using the 1st equation, arrange so we are solving for q (quarters)
\n" ); document.write( "d + q = 40
\n" ); document.write( " d = [40 - q]
\n" ); document.write( ":
\n" ); document.write( "Substitute [40-q] for d in the 2nd equation:
\n" ); document.write( ".10[40-q] + .25q > 6
\n" ); document.write( "4 - .10q + .25q > 6
\n" ); document.write( " .15q > 6 - 4
\n" ); document.write( " q > 2/.15
\n" ); document.write( " q > 13.33
\n" ); document.write( " q => 14 has to be an integer number\r
\n" ); document.write( "\n" ); document.write( "Check:
\n" ); document.write( "14 quarters + 26 dimes
\n" ); document.write( " 3.50 + 2.60 = $6.10 [fulfills the requirement of > $6]
\n" ); document.write( ":
\n" ); document.write( "Try 13 quarters + 27 dimes
\n" ); document.write( "3.25 + 2.70 = $5.95 less than the required $6
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