document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=535674>Question 535674</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a family with two children, find the probability of both being boys<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #351980 by </B><A HREF=/tutors/aboutme.mpl?userid=fcabanski><B>fcabanski(1391)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fcabanski><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=351980\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> With the given information, the P(boy) for any child is 1/2.  Extra info could have been given to show that the P(boy) or P(girl) would be more or less than 50%.  But absent info we have to assume 50% for each.<P>\r<BR>\n" );
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document.write( "These events are independent.  In other words, having a boy the first time doesn't change the probability of a boy the second time.  P(A AND B) = P(A)*P(B).<P>\r<BR>\n" );
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document.write( "P(BOY and BOY) = 1/2 * 1/2 = 1/4 = 25%<P><BR>\n" );
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