document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=535730>Question 535730</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I come up with the answer to this problem 2 5/2 - 2 3/2.  I have tried everything but I come up with 1 as the answer my prof says the correct answer is 2 3/2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #351978 by </B><A HREF=/tutors/aboutme.mpl?userid=fcabanski><B>fcabanski(1391)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fcabanski><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=351978\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The answer is 1.  In order for the answer to be 2 and 3/2 the first number has to be double 2 and 3/2.  That would be 14/2 or 7.<P><BR>\n" );
document.write( "You can either subtract the whole number from the whole number and the fraction from the fraction.  2-2=0 and (5/2) - (3/2) = 2/2 = 1.<P><BR>\n" );
document.write( "Or convert each to an improper fraction then subtract (multiple denominator by whole number, add the numerator - that's the new numerator and the denominator is the denominator of the existing fraction part.)<P><BR>\n" );
document.write( "(9/2) - (7/2) = 2/2 = 1\r<BR>\n" );
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