document.write( "Question 535570: A man travels 370 KM partly by train and partly by car. If he covers 250 KM by train and the rest by car. it takes him 4 Hours. But if he travels 130 KM by train and rest by car. he taken 18 minut longer. Find the speed of the train and that of the car. \n" ); document.write( "
Algebra.Com's Answer #351961 by mananth(16946)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "250/x + 120/y =4\r \n" ); document.write( "\n" ); document.write( "substitue 1/x with a & 1/y with b \n" ); document.write( "250a+120b=4\r \n" ); document.write( "\n" ); document.write( "130/x + 140/y = 4.3\r \n" ); document.write( "\n" ); document.write( "130a+140b=4.3\r \n" ); document.write( "\n" ); document.write( "250 a + 120 b = 4 .............1 \n" ); document.write( "130 a + 140 b = 4.3 .............2 \n" ); document.write( "Eliminate y \n" ); document.write( "multiply (1)by -7 \n" ); document.write( "Multiply (2) by 6 \n" ); document.write( "-1750 a -840 b = -28 \n" ); document.write( "780 a + 840 b = 25.8 \n" ); document.write( "Add the two equations \n" ); document.write( "-970 a = -2.2 \n" ); document.write( "/ -970 \n" ); document.write( "a = 0.00227 \n" ); document.write( "plug value of a in (1) \n" ); document.write( "250 a + 120 b = 4 \n" ); document.write( "0.57 + 120 b = 4 \n" ); document.write( " 120 b = 4 -0.57 \n" ); document.write( " 120 b = 3.43 \n" ); document.write( " b = 0.02861 \n" ); document.write( "x=1/a= 1/0.00227= 440 km/h-------------Train \n" ); document.write( "y=1/b=1/0.02861= 35 km/h-------------- Car\r \n" ); document.write( "\n" ); document.write( "CHECK \n" ); document.write( "130/440 +140/35= 4.3 hours\r \n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |