document.write( "Question 535570: A man travels 370 KM partly by train and partly by car. If he covers 250 KM by train and the rest by car. it takes him 4 Hours. But if he travels 130 KM by train and rest by car. he taken 18 minut longer. Find the speed of the train and that of the car. \n" ); document.write( "
Algebra.Com's Answer #351961 by mananth(16946)\"\" \"About 
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\n" ); document.write( "250/x + 120/y =4\r
\n" ); document.write( "\n" ); document.write( "substitue 1/x with a & 1/y with b
\n" ); document.write( "250a+120b=4\r
\n" ); document.write( "\n" ); document.write( "130/x + 140/y = 4.3\r
\n" ); document.write( "\n" ); document.write( "130a+140b=4.3\r
\n" ); document.write( "\n" ); document.write( "250 a + 120 b = 4 .............1
\n" ); document.write( "130 a + 140 b = 4.3 .............2
\n" ); document.write( "Eliminate y
\n" ); document.write( "multiply (1)by -7
\n" ); document.write( "Multiply (2) by 6
\n" ); document.write( "-1750 a -840 b = -28
\n" ); document.write( "780 a + 840 b = 25.8
\n" ); document.write( "Add the two equations
\n" ); document.write( "-970 a = -2.2
\n" ); document.write( "/ -970
\n" ); document.write( "a = 0.00227
\n" ); document.write( "plug value of a in (1)
\n" ); document.write( "250 a + 120 b = 4
\n" ); document.write( "0.57 + 120 b = 4
\n" ); document.write( " 120 b = 4 -0.57
\n" ); document.write( " 120 b = 3.43
\n" ); document.write( " b = 0.02861
\n" ); document.write( "x=1/a= 1/0.00227= 440 km/h-------------Train
\n" ); document.write( "y=1/b=1/0.02861= 35 km/h-------------- Car\r
\n" ); document.write( "\n" ); document.write( "CHECK
\n" ); document.write( "130/440 +140/35= 4.3 hours\r
\n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca
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