document.write( "Question 534652: Hello, I actually have 2 Questions.\r
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document.write( "1. 11^5x=72 to logarithmic form
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document.write( "I basically have to change that to the logarithmic form, and I wanted to know if this was the answer:log11 72= 5x?\r
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document.write( "2. ln(3x-1)=7 to exponential form
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document.write( "I have to change this problem to exponential form, and I do not know where to start. \n" );
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Algebra.Com's Answer #351951 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! 1. 11^5x=72 to logarithmic form \n" ); document.write( "I basically have to change that to the logarithmic form, and I wanted to know if this was the answer:log11 72= 5x? \n" ); document.write( "2. ln(3x-1)=7 to exponential form \n" ); document.write( "I have to change this problem to exponential form, and I do not know where to start. \n" ); document.write( "** \n" ); document.write( "1. 11^5x=72 \n" ); document.write( "take log of both sides \n" ); document.write( "5xlog11=log72 \n" ); document.write( "5x=log72/log11 \n" ); document.write( "x=(log72/log11)/5 \n" ); document.write( "use calculator to solve for x \n" ); document.write( ".. \n" ); document.write( "2. ln(3x-1)=7 \n" ); document.write( "Exponential form: Base(e) raised to log of the number(7)=number(3x-1) \n" ); document.write( "e^7=3x-1 \n" ); document.write( "3x=e^7+1≈1096.63 \n" ); document.write( "x≈1096.63/3≈365.54 \n" ); document.write( " |