document.write( "Question 535549: Jenny mixes a 30% saline solution with a 50% saline sloution to make 800 milliliters of a 45% saline solution. How many milliliters of each solution does she use ? \n" ); document.write( "
Algebra.Com's Answer #351933 by mananth(16946)\"\" \"About 
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percent ---------------- quantity
\n" ); document.write( "Saline I 30 ---------------- x ml
\n" ); document.write( "Saline II 50 ------ 800 - x ml
\n" ); document.write( "Mixture 45.00% ---------------- 800
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\n" ); document.write( "30x+50( 800-x) =45*800
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\n" ); document.write( "30x+40000-50x 36000
\n" ); document.write( "30x -50x= 36000 - 40000
\n" ); document.write( "-20 x= -4000
\n" ); document.write( "/ -20
\n" ); document.write( "x=200 ml30.00% Saline I
\n" ); document.write( "600ml50.00%Saline II
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