document.write( "Question 533576: amy's age = a, her brother's age = b
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document.write( "Amy is 6 years younger than her brother -> a = b-6. In four years, she will be half as old as her brother -> a+4 = 1/2x(b+4).
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document.write( "How old is each child? a, b = ? \n" );
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Algebra.Com's Answer #351874 by amalialaila(3)![]() ![]() ![]() You can put this solution on YOUR website! a = b-6 ...(i) \n" ); document.write( "a+4 = 1/2(b+4) ...(ii) \n" ); document.write( "substitute equation (i) to (ii) \n" ); document.write( "(b-6)+4 = 1/2(b+4) \n" ); document.write( "b-2 = 1/2(b+4) \n" ); document.write( "2(b-2) = b+4 \n" ); document.write( "2b-4 = b+4 \n" ); document.write( "unify the components with the same variable \n" ); document.write( "2b-b = 4+4 \n" ); document.write( "b = 8, this is amy's brother age. substitute the number to equation (i) \n" ); document.write( "a = 8-6 \n" ); document.write( "a = 2 \n" ); document.write( "amy's 2 years old and the brother is 8 years old. \n" ); document.write( " |