document.write( "Question 535335: a man when asked by his niece how old he was, he replied, My age is now 4x yours, but 5yrs ago it was 5x yours. (he is 80 but how do you solve it)
\n" ); document.write( "uncle's age = u , niece's age = n
\n" ); document.write( "u = 4n ...(i)
\n" ); document.write( "u-5 = 5(n-5) ...(ii)
\n" ); document.write( "

Algebra.Com's Answer #351858 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+x+\" be his age now
\n" ); document.write( "\"+x+-+5+\" is the man's age 5 years ago
\n" ); document.write( "given:
\n" ); document.write( "\"+x%2F4+\" is his niece's age now
\n" ); document.write( "\"+x%2F4+-+5+\" is his niece's age 5 years ago
\n" ); document.write( "\"+x+-+5+=+5%2A%28+x%2F4+-+5+%29+\"
\n" ); document.write( "\"+x+-+5+=+%285%2F4%29%2Ax+-+25+\"
\n" ); document.write( "\"+4x+-+20+=+5x+-+100+\"
\n" ); document.write( "\"+-20+=+x+-+100+\"
\n" ); document.write( "\"+100+-+20+=+x+\"
\n" ); document.write( "\"+x+=+80+\"
\n" ); document.write( "He is 80
\n" ); document.write( "
\n" );