document.write( "Question 535336: How do I solve 125x^3 + 343 = 0? \n" ); document.write( "
Algebra.Com's Answer #351857 by stanbon(75887)\"\" \"About 
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solve 125x^3 + 343 = 0
\n" ); document.write( "Modify:
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\n" ); document.write( "(5x)^3 + 7^3 = 0
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\n" ); document.write( "Factor:
\n" ); document.write( "(5x+7)((5x)^2-(5x)(7)+7^2) = 0
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\n" ); document.write( "(5x+7)(25x^2-35x+49) = 0
\n" ); document.write( "One of those factors must be zero:
\n" ); document.write( "If 5x+7 = 0
\n" ); document.write( "x = -7/5
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\n" ); document.write( "If 25x^2-35x+49 = 0
\n" ); document.write( "x = [35 +- sqrt(35^2 - 4*25*49)]/50
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\n" ); document.write( "x = [35 +- sqrt(-3675)]/50
\n" ); document.write( "---
\n" ); document.write( "x = (7/10) +- (60.62/50)i
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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