document.write( "Question 535336: How do I solve 125x^3 + 343 = 0? \n" ); document.write( "
Algebra.Com's Answer #351857 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! solve 125x^3 + 343 = 0 \n" ); document.write( "Modify: \n" ); document.write( "---- \n" ); document.write( "(5x)^3 + 7^3 = 0 \n" ); document.write( "--- \n" ); document.write( "Factor: \n" ); document.write( "(5x+7)((5x)^2-(5x)(7)+7^2) = 0 \n" ); document.write( "---- \n" ); document.write( "(5x+7)(25x^2-35x+49) = 0 \n" ); document.write( "One of those factors must be zero: \n" ); document.write( "If 5x+7 = 0 \n" ); document.write( "x = -7/5 \n" ); document.write( "---- \n" ); document.write( "If 25x^2-35x+49 = 0 \n" ); document.write( "x = [35 +- sqrt(35^2 - 4*25*49)]/50 \n" ); document.write( "--- \n" ); document.write( "x = [35 +- sqrt(-3675)]/50 \n" ); document.write( "--- \n" ); document.write( "x = (7/10) +- (60.62/50)i \n" ); document.write( "============================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "==================== \n" ); document.write( " \n" ); document.write( " |