document.write( "Question 535335: a man when asked by his niece how old he was, he replied, My age is now 4x yours, but 5yrs ago it was 5x yours. (he is 80 but how do you solve it)
\n" ); document.write( "uncle's age = u , niece's age = n
\n" ); document.write( "u = 4n ...(i)
\n" ); document.write( "u-5 = 5(n-5) ...(ii)
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Algebra.Com's Answer #351856 by fcabanski(1391)\"\" \"About 
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\n" ); document.write( "Y = Man's age


\n" ); document.write( "X = neice's age

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\n" ); document.write( "\n" ); document.write( "Currently y = 4x


\n" ); document.write( "5 years ago y-5 = 5 (x-5) Five years ago the man was y-5 years old, current age - 5. Neice was x-5 years old, current age - 5. And the man (y-5) was 5 times older than the neice 5*(x-5).

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\n" ); document.write( "\n" ); document.write( "Substitute the value of y, in terms of x, from the first equation into the second. Then solve for x.


\n" ); document.write( "4x-5=5(x-5) ---> 4x-5=5x-25 (subtract 4x from both sides, add 25 to both sides.


\n" ); document.write( "20=x. Remember the man is currently 4x old, and 4(20)=80. \n" ); document.write( "

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