document.write( "Question 535257: How much water must be added to 12 L of a 40% solution of alcohol to obtain a 30% solution?
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Algebra.Com's Answer #351848 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
I will pretend that I am not a chemist, because from the point of view of a chemist, this problem is so wrong on multiple levels that it makes me want to cry.
\n" ); document.write( "Let the volume of water that must be added be \"x\".
\n" ); document.write( "The amount of alcohol in the solution is 40% of 12L, or
\n" ); document.write( "\"0.40%2A12L=4.8L\"
\n" ); document.write( "If that amount is to be 30% of the expected volume (in liters) of \"12%2Bx\",
\n" ); document.write( "then \"0.30%2A%2812%2Bx%29=4.8\"
\n" ); document.write( "\"3.6%2B0.30x=4.8\" --> \"0.30x=1.2\" -->\"x=1.2%2F0.30\" --> \"x=4.0\"
\n" ); document.write( "You need to add 4.0L water.
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