document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=535263>Question 535263</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i have to find a quadratic function in standard form for these set of points (-1,2),(0,1),(1,-4) <BR>\n" );
document.write( "i dont get how to though </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #351844 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=351844\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y = ax^2 + bx + c ___ plug the points into the general equation<BR>\n" );
document.write( "___ then solve the resulting linear system for the coefficients (a, b, c)\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "2 = a(-1)^2 + b(-1) + c ___ 2 = a - b + c\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "1 = a(0)^2 + b(0) + c ___ 1 = c\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "-4 = a(1)^2 + b(1) + c ___ -4 = a + b + c </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );