document.write( "Question 52749: 13+5x-2x=37 what does x equal show work thanks \n" ); document.write( "
Algebra.Com's Answer #35183 by AnlytcPhil(1806)\"\" \"About 
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13+5x-2x=37 what does x equal show work thanks\r\n" );
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document.write( "13 + 5x - 2x = 37\r\n" );
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document.write( "First combine the like terms on the left which are\r\n" );
document.write( "+5x and -2x.  That gives you +3x. So you replace\r\n" );
document.write( "\"+ 5x - 2x\" by \"+ 3x\". So now you have this:\r\n" );
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document.write( "    13 + 3x = 37 \r\n" );
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document.write( "Since you want to get the x-term, +3x, all by itself\r\n" );
document.write( "we get rid of the 13 term on the left by adding its\r\n" );
document.write( "opposite, -13, to both sides\r\n" );
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document.write( "    13 + 3x = 37\r\n" );
document.write( "   -13       -13\r\n" );
document.write( "------------------\r\n" );
document.write( "         3x = 24\r\n" );
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document.write( "When we get to this stage, where there is just one \r\n" );
document.write( "term on the left consisting of a coefficient and the\r\n" );
document.write( "unknown, then you divide both sides by that \r\n" );
document.write( "coefficient, which is 3.\r\n" );
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document.write( "         3x     24\r\n" );
document.write( "        ---- = ----\r\n" );
document.write( "          3      3\r\n" );
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document.write( "Then the 3's cancel on the left and the 3 goes into the\r\n" );
document.write( "24 8 times on the right:\r\n" );
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document.write( "         1       8\r\n" );
document.write( "         3x     24\r\n" );
document.write( "        ---- = ----\r\n" );
document.write( "          3      3\r\n" );
document.write( "          1      1\r\n" );
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document.write( "so the answer is:\r\n" );
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document.write( "           x = 8\r\n" );
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document.write( "Edwin
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