document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=535253>Question 535253</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the distance between the points (1,1) nad (-0.5,-1)<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #351814 by </B><A HREF=/tutors/aboutme.mpl?userid=fcabanski><B>fcabanski(1391)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fcabanski><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=351814\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <B>Check my profile and contact me for one on one online tutoring.</B><P>\r<BR>\n" );
document.write( "\n" );
document.write( "The distance formula for the distance between two points is d = sqrt ((x2-x1)^2 + (y2-y1)^2).<P>\r<BR>\n" );
document.write( "\n" );
document.write( "In this case we'll call (1,1) point 1 and (-0.5,-1) point 2.<P>\r<BR>\n" );
document.write( "\n" );
document.write( "d = sqrt ((-.5-1)^2 + (-1-1)^2) = sqrt (2.25+4) = sqrt (6.25) = 2.5. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );