document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=535139>Question 535139</A>: <I><SPAN STYLE=\"word-break: break-all;\"> howw does:\r<BR>\n" );
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document.write( "tan ([pi] + alpha)= tan (alpha)\r<BR>\n" );
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document.write( "i tried using the sum and difference formula like it says in the directions but it isnt helping much.\r<BR>\n" );
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document.write( "i use the formula:<BR>\n" );
document.write( "tan ([pi]) + tan(alpha) all divided by 1- tan( [pi] tan alpha) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #351797 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=351797\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> howw does: <BR>\n" );
document.write( "tan ([pi] + alpha)= tan (alpha) <BR>\n" );
document.write( "i tried using the sum and difference formula like it says in the directions but it isnt helping much. <BR>\n" );
document.write( "i use the formula:<BR>\n" );
document.write( "tan ([pi]) + tan(alpha) all divided by 1- tan( [pi] tan alpha)<BR>\n" );
document.write( "**<BR>\n" );
document.write( "using x for alpha<BR>\n" );
document.write( "tan(x+&#960;)=(tanx+tan&#960;)/(1-tanxtan&#960;)<BR>\n" );
document.write( "tan&#960;=0<BR>\n" );
document.write( "tan(x+&#960;)=(tanx+0)/(1-tanx*0)=tanx/1=tanx<BR>\n" );
document.write( "tan(x+&#960;)=tanx<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Physically, in a unit circle,you are advancing the angle &#960; radians which places the angle x in a quadrant where the reference angle is equal to x and the sign of the tan function does not change. For example, if x were 21º, advancing it 180º places it in quadrant III where tan>0, and the reference angle is 21º </SPAN>\n" );
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