document.write( "Question 535179: What is the dimension of a rectangle with a perimeter of 460 feet? \n" ); document.write( "
Algebra.Com's Answer #351791 by lmeeks54(111)![]() ![]() You can put this solution on YOUR website! There are several (actually an infinite number of) rectangles that have perimeter = 460 ft. The basis for solving this problem is understanding the equation for the perimeter of a rectangle. The perimeter of an area is the distance around the outside of that area. If your rectangle is a square (a special type of rectangle), just add up a walk around the 4 sides... \n" ); document.write( "... \n" ); document.write( "Let P = length of the perimeter \n" ); document.write( "Let S = the length of one of the square's 4 sides \n" ); document.write( "... \n" ); document.write( "P = S + S + S + S = 4S \n" ); document.write( "... \n" ); document.write( "Consider a more 'traditional' rectangle with 2 long sides of equal length and 2 short sides of equal length: \n" ); document.write( "... \n" ); document.write( "Let P = perimeter \n" ); document.write( "Let L = the length of the long sides \n" ); document.write( "Let S = the length of the short sides \n" ); document.write( "... \n" ); document.write( "P = 2L + 2S \n" ); document.write( "... \n" ); document.write( "We're given P = 460 ft. So, any combination of 2L + 2S that totals 460 solves this problem. \n" ); document.write( "... \n" ); document.write( "For example, let's test this, let L = 200 and S = 30: \n" ); document.write( "460 = 2(200) + 2(30) \n" ); document.write( "460 = 400 + 60 \n" ); document.write( "460 = 460 \n" ); document.write( "... \n" ); document.write( "Try another one, let L = 229 and S = 1: \n" ); document.write( "460 = 2(229) + 2(1) \n" ); document.write( "460 = 458 + 2 \n" ); document.write( "460 = 460 \n" ); document.write( "... \n" ); document.write( "We could keep going on and on like this. \n" ); document.write( "... \n" ); document.write( "Cheers, \n" ); document.write( "Lee \n" ); document.write( " |