document.write( "Question 535147: It was found out that average intake of medicine in a group of patients is 110mg with standard deviation 10mg per week.
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document.write( "(a) a patient is chosen at random. Find the probability that his/her intake is in betweem 100mg and 115mg per week.
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document.write( "(b) a sample of 3 patients is chosen at random. Find the probability that the sample mean (average) intake exceeds 115mg per week. \n" );
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Algebra.Com's Answer #351783 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! It was found out that average intake of medicine in a group of patients is 110mg with standard deviation 10mg per week. \n" ); document.write( "------------------------------- \n" ); document.write( "(a) a patient is chosen at random. Find the probability that his/her intake is in betweem 100mg and 115mg per week. \n" ); document.write( "z(100) = (100-110)/10 = -1 \n" ); document.write( "z(115) = (115-110)/10 = 1/2 \n" ); document.write( "P(100 < x < 115) = P(-1< z <1/2) = 0.5328 \n" ); document.write( "------------------------------------------ \n" ); document.write( "(b) a sample of 3 patients is chosen at random. Find the probability that the sample mean (average) intake exceeds 115mg per week. \n" ); document.write( "t(115) = (115-110)/(10/sqrt(3)) = 5/(10/sqrt(3)) = 0.8660 \n" ); document.write( "--- \n" ); document.write( "P(x > 115) = P(t > 0.8660 when df = 2) = 0.2388 \n" ); document.write( "================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============== \n" ); document.write( " |