document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=535071>Question 535071</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The resistance of a wire is inversely proportional to the square of its diameter.  If an AWG (American wire gauge) size 12 conductor (0.0808-in. diameter) has a resistance of 14.8, what will be the resistance of an AWG size 10 conductor (0.1019-in. diameter) of the same length and material? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #351751 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=351751\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 14.8*0.0808^2 = R*0.1019^2<BR>\n" );
document.write( "R = 14.8*0.0808^2/0.1019^2<BR>\n" );
document.write( "R =~ 9.3 ohms<BR>\n" );
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