document.write( "Question 535026: A plane traveled 624 miles to Perth and back. The trip there was with the wind. It took four hours. The trip back was into the wind. The trip back took 6 hours. What is the speed of the plane in still air? What is the speed of the wind? \r
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document.write( "I really need help on this one and would be so greatful to anyone that would show me the answer. \n" );
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Algebra.Com's Answer #351750 by mananth(16946) You can put this solution on YOUR website! plane speed =x mph \n" ); document.write( "wind speed speed =y mph \n" ); document.write( "against current x-y 6.00 hours \n" ); document.write( "With current x+y 4.00 hours \n" ); document.write( " \n" ); document.write( "Distance = same= 624 miles \n" ); document.write( "t=d/r \n" ); document.write( "624 / ( x - y )= 6.00 \n" ); document.write( "6 ( x - y ) = 624.00 \n" ); document.write( "6 x -6 y = 624 ....................1 \n" ); document.write( "624 / ( x + y )= 4.00 \n" ); document.write( "4.00 ( x + y ) = 624 \n" ); document.write( "4.00 x + 4.00 y = 624 ...............2 \n" ); document.write( "Multiply (1) by 2.00 \n" ); document.write( "Multiply (2) by 3.00 \n" ); document.write( "we get \n" ); document.write( "12 x + -12 y = 1248 \n" ); document.write( "12 x + 12 y = 1872 \n" ); document.write( "24 x = 3120 \n" ); document.write( "/ 24 \n" ); document.write( "x = 130 mph \n" ); document.write( " \n" ); document.write( "plug value of x in (1) \n" ); document.write( "6 x -6 y = 624 \n" ); document.write( "780 -6 y = 624 \n" ); document.write( "-6 y = 624 -780 \n" ); document.write( "-6 y = -156 \n" ); document.write( " y = 26 mph \n" ); document.write( " plane 130 mph \n" ); document.write( " wind speed 26 mph \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |