document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=535052>Question 535052</A>: <I><SPAN STYLE=\"word-break: break-all;\"> An individual has two low-interest loans, one at 4% interest and the other at 6% interest. The amount borrowed at 6% is $250 more than the amount borrowed at 4%. If the total interest for one year is $165, how much money is borrowed at each rate? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #351745 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=351745\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Amount @	4.00%	x 							<BR>\n" );
document.write( "Amount @	6.00%	1	x	+	250				<BR>\n" );
document.write( "Total interest paid =		165							<BR>\n" );
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document.write( "4.00%	x+	6.00%	(	1	x	+	250	)=	165<BR>\n" );
document.write( "4.00%	x+	6.00%	*	1	x	+	15	=	165<BR>\n" );
document.write( "4.00%	x+	0.06	x	+	15		=	165	<BR>\n" );
document.write( "0.04	x+	0.06	x	=	150				<BR>\n" );
document.write( "0.1	x	=	150						<BR>\n" );
document.write( "	x=	1500	Amount @	4.00%					<BR>\n" );
document.write( "									<BR>\n" );
document.write( "Amount @	6.00%	=1500	+	250 =	1750						<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );