document.write( "Question 534996: Working together, Butch and Manny can paint a wall in 3 hours. Working alone, Butch can do the job in 5 hours. How long will it take Manny to do the job alone?
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Algebra.Com's Answer #351728 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Let x=amount of time it takes Manny to do the job alone \n" ); document.write( "Working alone Manny paints at the rate of 1/x wall per hour \n" ); document.write( "Working together Butch and Manny paints at the rate of 1/3 wall per hour \n" ); document.write( "Working alone Butch paints at the rate of 1/5 wall per hour\r \n" ); document.write( "\n" ); document.write( "Sooooo, our equation to solve is: \n" ); document.write( "1/x + 1/5=1/3 multiply each term by 15x \n" ); document.write( "15+3x=5x \n" ); document.write( "2x=15 \n" ); document.write( "x=7.5 hrs------amount of time it takes Manny to do the job alone\r \n" ); document.write( "\n" ); document.write( "CK \n" ); document.write( "In 3 hrs Manny paints 3/(7.5) of the wall \n" ); document.write( "In 3 hrs, Butch paints 3/5 of the wall \n" ); document.write( "3/(7.5)+3/5 should equal 1 (1 wall that is) \n" ); document.write( "6/15+9/15=15/15=1 \n" ); document.write( "1=1\r \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( " |