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please help me graph this equation: y=2sin(x/2-pi/3)
\n" ); document.write( "**
\n" ); document.write( "Equation used to graph sin function: y=Asin(Bx-C), A=amplitude, Period =2π/B, C/B=Phase shift
\n" ); document.write( "For given sin function:
\n" ); document.write( "A=2
\n" ); document.write( "B=1/2
\n" ); document.write( "Period: 2π/B=2π/(1/2)=4π
\n" ); document.write( "1/4 period=π
\n" ); document.write( "Phase shift:C/B=(π/3)/(1/2)=2π/3 (shift to right)
\n" ); document.write( "..
\n" ); document.write( "Graphing: (For one period)
\n" ); document.write( "Let us first graph the basic sin function for one period
\n" ); document.write( "On the x-axis make tick marks at π, 2π, 3π and 4π representing one period.
\n" ); document.write( "This will give you the following points:
\n" ); document.write( "(0,0), (π,1), (2π,0), (3π,-1), (4π,0)
\n" ); document.write( "multiply the y-coordinates by 2
\n" ); document.write( "(0,0), (π,2), (2π,0), (3π,-2), (4π,0)
\n" ); document.write( "add 2π/3 to the x-coordinates (shifting the curve 2π/3 to the right)
\n" ); document.write( "(2π/3,0), (5π/3,2), (8π/3,0), (11π/3,-2), (6π,0)
\n" ); document.write( "y-intercept
\n" ); document.write( "set x=0
\n" ); document.write( "0=2(sin -π/3)=-√3/2*2=-1.732
\n" ); document.write( "y-intercept=-1.732
\n" ); document.write( "You now have these points and the y-intercept with which you can graph the given function:
\n" ); document.write( "note: When plotting the curve, you need to convert the y-values to numbers with decimals, ie, 2π/3=2.0944, 5π/3=5.2360, etc \n" ); document.write( "