document.write( "Question 534799: Identify all Maximums Points, Minimum Points, and Points of Inflections for the function (x+3)/(x^2-16).
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document.write( "I am not sure. I am thinking that ff there is no point at which the first derivative is equal to 0, then it is impossible for there to be a point at which both the second and first derivative are equal to 0, making the answer for all three points (Maximum, Minimum, and Points of Inflection) none. \r
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document.write( "My domain is all values of x except x=-2 & x=2. My range is (-infinity, infinity).\r
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document.write( "Thank you! :) \n" );
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Algebra.Com's Answer #351694 by KMST(5328)![]() ![]() You can put this solution on YOUR website! If it's really \n" ); document.write( "the points where it does not exist are x=-4 and x=4, and all other x are in the domain. \n" ); document.write( "I agree that the range is (-infinity, infinity). \n" ); document.write( "If that's really the function, it changes sign 3 times (at -4, -3 an 3), with vertical asymptotes at \n" ); document.write( "and a zero at \n" ); document.write( "There is no minimum or maximum. The first derivative is always negative, so the function decreases continuously in each of the 3 regions where it exists, going from positive infinity at the right of vertical asymptote \n" ); document.write( "down to negative infinity on the left of vertical asymptote \n" ); document.write( "To hug those vertical asymptotes like that, the function has to go from concave upwards to concave downwards. The second derivative must have an inflection point somewhere between them. I calculated it, but I may have made a mistake. I got \n" ); document.write( "which is zero at a point near \n" ); document.write( "You do not need both derivatives to be zero to have an inflection point. \n" ); document.write( "If they are both zero, it is a saddle point, an inflection point where the slope is zero. An example of a function with an inflection point where the first derivative is not zero is \n" ); document.write( " \n" ); document.write( " |