document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=534728>Question 534728</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Will you help me with substitution 3x+y=24  y=3x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #351687 by </B><A HREF=/tutors/aboutme.mpl?userid=Iluvidina><B>Iluvidina(15)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Iluvidina><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Iluvidina><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=351687\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Y=12; x=4\r<BR>\n" );
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document.write( "I started with y=3x, because it is the easiest to figure out what one of the variables equals<BR>\n" );
document.write( "I divided each side by 3. The equation then was 1/3y=x<BR>\n" );
document.write( "Then, I substituted that in the other equation for x<BR>\n" );
document.write( "The equation 3x+y=24 became 3(1/3y)+y=24<BR>\n" );
document.write( "Then you multiply 3 by 1/3y, becoming (1)y+y=24<BR>\n" );
document.write( "y+y becomes 2y, so the equatiion becomes 2y=24<BR>\n" );
document.write( "Then you divide each side by 2, becoming y=12<BR>\n" );
document.write( "Then you substitute y for 12 in the equation y=3x. So, it would be 12=3x.<BR>\n" );
document.write( "Then you divide 3 on both sides, becoming x=4 </SPAN>\n" );
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