document.write( "Question 534886: solve please $\"x%5E3%2B3x%5E2-4x=0\"$ \n" ); document.write( "

Algebra.Com's Answer #351678 by Earlsdon(6294) $\"\"$ $\"About$

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Solve for x:
\n" ); document.write( " $\"x%5E3%2B3x%5E2-4x+=+0\"$ Since this is a cubic (3rd order) equation, you can expect to find 3 solutions.
\n" ); document.write( " $\"x%5E3%2B3x%5E2-4x+=+0\"$ First factor an x.
\n" ); document.write( " $\"x%28x%5E2%2B3x-4%29+=+0\"$ Apply the zero product rule.
\n" ); document.write( " $\"x+=+0\"$ or $\"x%5E2%2B3x-4+=+0\"$ Now factor the trinomial.
\n" ); document.write( " $\"%28x-1%29%28x%2B4%29+=+0\"$ Apply the zero product rule.
\n" ); document.write( " $\"x-1+=+0\"$ or $\"x%2B4+=+0\"$ so...
\n" ); document.write( " $\"x+=+1\"$ or $\"x+=+-4\"$
\n" ); document.write( "The three solutions are:
\n" ); document.write( " $\"x+=+0\"$
\n" ); document.write( " $\"x+=+1\"$
\n" ); document.write( " $\"x+=+-4\"$ \n" ); document.write( "

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