document.write( "Question 534837: How much water must be added to 20 ounces of a 60% saline solution to obtain a 45% saline solution? \n" ); document.write( "

Algebra.Com's Answer #351660 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"x\"$ = ounces of water to be added
\n" ); document.write( "given:
\n" ); document.write( "Salt in 60% solution = $\"+.6%2A20+=+12+\"$ ounces
\n" ); document.write( " $\"+12+%2F+%28+20+%2B+x+%29+=+.45+\"$
\n" ); document.write( " $\"+12+=+.45%2A%28+20+%2B+x+%29+\"$
\n" ); document.write( " $\"+12+=+9+%2B+.45x+\"$
\n" ); document.write( " $\"+.45x+=+3+\"$
\n" ); document.write( " $\"+x+=+6.666+\"$
\n" ); document.write( "6.666 ounces of water should be added \n" ); document.write( "

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