document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=534779>Question 534779</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I use substitution to get the answer x=0 and y=-4 for these problems: 10x+3y= -12<BR>\n" );
document.write( "5x+4y= -16\r<BR>\n" );
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document.write( "I've tried quite a few times and keep getting fractions. Please help. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #351641 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=351641\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 10	x	+	3	y	=	-12	.............1				<BR>\n" );
document.write( "4	y	=	-16		-5	x	---------2				<BR>\n" );
document.write( "/	4	=									<BR>\n" );
document.write( "	y	=	-4		-1.25	x					<BR>\n" );
document.write( "Substitute y in 		(1)									<BR>\n" );
document.write( "10x+3(-4-1.25x	)=	-12<BR>\n" );
document.write( "10x-12+	-3.75x	=	-12			<BR>\n" );
document.write( "10x-3.75x	=	-12	12				<BR>\n" );
document.write( "6.25	x	=	0								<BR>\n" );
document.write( "/	6.25										<BR>\n" );
document.write( "x=	0										<BR>\n" );
document.write( "Plug the value of x in (1)											<BR>\n" );
document.write( "10x+3=	-12					<BR>\n" );
document.write( "10*0+3y	=	-12				<BR>\n" );
document.write( "0+3y=-12						<BR>\n" );
document.write( "3y=-12								<BR>\n" );
document.write( "/	3										<BR>\n" );
document.write( "y=	-4										<BR>\n" );
document.write( "m.ananth@hotmail.ca											<BR>\n" );
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