document.write( "Question 534786: I am stuck on how to solve the problem 6^-3x=15
\n" ); document.write( "I do not understand logrithms at all.\r
\n" ); document.write( "\n" ); document.write( "Thank you for your help.\r
\n" ); document.write( "\n" ); document.write( "LC
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Algebra.Com's Answer #351638 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Suppose I say \"+z+=+-3x+\"
\n" ); document.write( "Then
\n" ); document.write( "\"+6%5Ez+=+15+\"
\n" ); document.write( "I know that
\n" ); document.write( "\"+6%5E1+=+6+\"
\n" ); document.write( "\"+6%5E2+=+36+\"
\n" ); document.write( "So, \"z\" is somewhere between \"1\" and \"2\"
\n" ); document.write( "and,
\n" ); document.write( "\"+1+=+-3x+\"
\n" ); document.write( "\"+x+=+-%281%2F3%29+\"
\n" ); document.write( "\"+2+=+-3x+\"
\n" ); document.write( "\"+x+=+-%282%2F3%29+\"
\n" ); document.write( "so, \"x\" must be between -(2/3) and -(1/3)
\n" ); document.write( "You could find the answer by trying
\n" ); document.write( "\"+6%5E1.1+\"
\n" ); document.write( "\"+6%5E1.2+\"
\n" ); document.write( "etc
\n" ); document.write( "on a calculator until you get very, very close to 15
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