document.write( "Question 534744: The formule D=0.054x^2+0.058x describes the distance in feet D that it takes to stop a vehicle traveling x miles per hour on dry pavement.\r
\n" ); document.write( "\n" ); document.write( "a. How fast can you drive if you wish to be able to stop your car within 65 feet?\r
\n" ); document.write( "\n" ); document.write( "b.On black ice, a truck's stopping distance is 3 times its stopping distance on dry pavement. A truck traveling 20 miles per hour applies the brakes, on black ice, at a distance of 65 feet in front of a rubber traffic cone. Will the truck hit the cone?
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Algebra.Com's Answer #351631 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
The formule D=0.054x^2+0.058x describes the distance in feet D that it takes to stop a vehicle traveling x miles per hour on dry pavement.
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\n" ); document.write( "a. How fast can you drive if you wish to be able to stop your car within 65 feet?
\n" ); document.write( "Solve: 0.054x^2+0.058x = 65
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\n" ); document.write( "Graph to find \"x\":
\n" ); document.write( "Ans: 34.16 mph
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\n" ); document.write( "b.On black ice, a truck's stopping distance is 3 times its stopping distance on dry pavement. A truck traveling 20 miles per hour applies the brakes, on black ice, at a distance of 65 feet in front of a rubber traffic cone. Will the truck hit the cone?
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\n" ); document.write( "Normal stopping distance:
\n" ); document.write( "D(20) = 0.54*20^2+0.058*20 = 22.76 ft.
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\n" ); document.write( "On black ice: 3*22.76 = 68.28 ft
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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