document.write( "Question 52689: i have a jar with 40 coins that consist of dimes and quarters that amount to$ 4.90 how quarters and dimes do you have? \n" ); document.write( "
Algebra.Com's Answer #35163 by funmath(2933)![]() ![]() ![]() You can put this solution on YOUR website! Let the amount of dimes = x \n" ); document.write( "Then the rest of the coins are quarters, let the amount of quarters=40-x \n" ); document.write( "It's often easier to solve these problems in terms of cents; the amount of money you have is the worth of the coin times the amount of the coins. \n" ); document.write( "The amount of money in dimes that he has = 10x \n" ); document.write( "The amount of quarters that he has = 25(40-x) \n" ); document.write( "The total amount of money he has in cents = 490 cents \n" ); document.write( "The problem to solve: \n" ); document.write( "10x+25(40-x)=490 \n" ); document.write( "10x+1000-25x=490 \n" ); document.write( "-15x+1000=490 \n" ); document.write( "-15x+1000-1000=490-1000 \n" ); document.write( "-15x=-510 \n" ); document.write( "-15x/-15=-510/-15 \n" ); document.write( "x=34 \n" ); document.write( "The amount of dimes that he has is 34. \n" ); document.write( "The amount of quarters that he has is 40-34=6. \n" ); document.write( "If you want to check your answer, just count it up the wat that you would any money. You'll see that you have $4.90. \n" ); document.write( " |