document.write( "Question 52685: Stan invested $17,000, part at 18% and part at 4%. If the total interest at the end of the year is $1,380, how much did he invest at each rate? \n" ); document.write( "
Algebra.Com's Answer #35162 by funmath(2933)\"\" \"About 
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Let the amount of principle invested at 18%=x
\n" ); document.write( "Then the amount invested at 4% would be 17,000-the amount he invested at 18%=17,000-x
\n" ); document.write( "time = 1
\n" ); document.write( "interest=1,380
\n" ); document.write( "Interest = principle*rate*time
\n" ); document.write( "1,380=.18x+.04(17,000-x)Multiply both sides by 100 to clear the decimals.
\n" ); document.write( "100(1,380)=100(.18x+.04(17,000-x))
\n" ); document.write( "100(1,380)=100(.18x)+100(.04)(17,000-x)
\n" ); document.write( "138,000=18x+4(17,000-x)
\n" ); document.write( "138,000=18x+4(17,000)+4(-x)
\n" ); document.write( "138,000=18x+68,000-4x
\n" ); document.write( "138,000=(18-4)x+68,000
\n" ); document.write( "138,000=14x+68,000
\n" ); document.write( "138,000-68,000=14x+68,000-68,000
\n" ); document.write( "70,000=14x
\n" ); document.write( "70,000/14=14x/14
\n" ); document.write( "5,000=x
\n" ); document.write( "There was $5,000 invested at 18%
\n" ); document.write( "There was 17,000-5,000=$12,000 invested at 4%
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