document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=52631>Question 52631</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The additive inverse of the number 1 + 4i is:\r<BR>\n" );
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document.write( "  a. -1 + 4i    <BR>\n" );
document.write( "  b. 1/17 - 4/17 i    <BR>\n" );
document.write( "  c. -1 - 4i    <BR>\n" );
document.write( "  d. 1 - 4i     </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #35160 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=35160\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The additive inverse of the number 1 + 4i is:<BR>\n" );
document.write( "additive identity element is 0+0i...since (a+bi)+(0+0i)=a+bi<BR>\n" );
document.write( "so additive inverse of 1+4i   is   -1-4i...since 1+4i-1-4i=0+0i<BR>\n" );
document.write( "a. -1 + 4i<BR>\n" );
document.write( "b. 1/17 - 4/17 i<BR>\n" );
document.write( "c. -1 - 4i<BR>\n" );
document.write( "d. 1 - 4i  </SPAN>\n" );
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