document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=534553>Question 534553</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am having trouble with this lesson, I've tried this problem and cannot figure it out. If you could please help me understand the process that would be wonderful.\r<BR>\n" );
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document.write( "A dairy needs 255 gallons of milk containing 5% butterfat.<BR>\n" );
document.write( "How many gallons each of milk containing 6% butterfat and milk containing 1% butterfat must be used to obtain the desired 255 gallons?\r<BR>\n" );
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document.write( "I have a box for each % of butterfat used(____of 5%   ____of 1%)\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #351583 by </B><A HREF=/tutors/aboutme.mpl?userid=Maths68><B>Maths68(1474)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Maths68><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Maths68><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=351583\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> \r<BR>\n" );
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document.write( "One kind of Milk<BR>\n" );
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document.write( "Amount = x gallons<BR>\n" );
document.write( "Butterfat = 6% = 6/100 = 0.06\r<BR>\n" );
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document.write( "other kind of Milk<BR>\n" );
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document.write( "Amount = 255-x gallons<BR>\n" );
document.write( "Butterfat=1%=1/100=0.01\r<BR>\n" );
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document.write( "Mixture Milk<BR>\n" );
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document.write( "Amount = 255 gallons<BR>\n" );
document.write( "Butterfat = 5% = 5/100 = 0.05\r<BR>\n" );
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document.write( "(Amount of on kind of milk)*(Buttefat)+ (Amount of other kind of milk)*(Buttefat)=(Amount of Mixture milk)*(Buttefat)<BR>\n" );
document.write( "(x)(0.06)+(255-x)(0.01)=255*0.05<BR>\n" );
document.write( "0.06x+2.55-0.01x=12.75<BR>\n" );
document.write( "0.06x-0.01x=12.75-2.55<BR>\n" );
document.write( "0.05x=10.2<BR>\n" );
document.write( "0.05x/0.05=10.2/0.05<BR>\n" );
document.write( "x=204\r<BR>\n" );
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document.write( "One kind of Milk<BR>\n" );
document.write( "=================<BR>\n" );
document.write( "Amount = x = 204 gallons<BR>\n" );
document.write( "Butterfat = 6% = 6/100 = 0.06\r<BR>\n" );
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document.write( "other kind of Milk<BR>\n" );
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document.write( "Amount = 255-204 = 51 gallons<BR>\n" );
document.write( "Butterfat=1%=1/100=0.01\r<BR>\n" );
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document.write( "Conclusion<BR>\n" );
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document.write( "204 gallons of Milk containing 6% butterfat and 51 gallons of milk containing 1% butterfat must be used to obtain the desired 255 gallons containing 5% butterfat.\r<BR>\n" );
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