document.write( "Question 52654: Determine if each of the following is a relation or a function. Tell why and give the domain and range of each one.\r
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document.write( "a) (0,1)(4,1)(6,2)(2,0)\r
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document.write( "b) y=6 over 2x-1 \n" );
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Algebra.Com's Answer #35157 by funmath(2933)![]() ![]() ![]() You can put this solution on YOUR website! a) (0,1), (4,1), (6,2), (2,0) \n" ); document.write( "This is a function because for every x there is exactly one y. Y's can have more than one x, but x's can have only one y. \n" ); document.write( "The Domain corresponds with the x values is {0,4,6,2}, the range corresponds with the y values is {1,1,2,0} \n" ); document.write( "b) y=6/(2x-1) \n" ); document.write( "This is a function. When dealing with equations it is often easiest to look at y. If it's not raised to an even power it's a function. \n" ); document.write( "For rational (fractions with variables in the denominator) functions the domain can be found by finding out what makes the denominator =0 (thus be undefined) \n" ); document.write( "2x-1=0 \n" ); document.write( "2x-1+1=0+1 \n" ); document.write( "2x=1 \n" ); document.write( "2x/2=1/2 \n" ); document.write( "x cannot = 1/2 \n" ); document.write( "Set builder notation:{x|x cannot=1/2} \n" ); document.write( "Interval notation: (- infinity, 1/2)U(1/2,+infinity) \n" ); document.write( "For the Range: y cannot eqaul 0. \n" ); document.write( "Set builder notation:{y|y cannot=0} \n" ); document.write( "Interval:(-infinity,0)U(0,+infinity) \n" ); document.write( "I don't know what math you're taking, so I don't want to tell you too much about how I know the range and freak you out. Resubmit that portion with the level of math you're in and I'll tell you how to find out that y cannot = 0. If you're in algebra, you can probably just plug it into your graphing calculator and look at what y can't be. If your in precal or calculus, take the limit as x approaches infinity. \n" ); document.write( " |