document.write( "Question 534358: How do I use two variables and two equations to solve this problem. A machine in a
\n" ); document.write( "pottery factory takes 3 minutes to form a bowl and 2 minutes to form a plate. The material for a bowl costs $0.25, and the material for a plate costs $0.20. If the machine runs for 8 hours and exactly $44 is spent for material, how many bowls and plates can be produced? How do I set it up?
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Algebra.Com's Answer #351561 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
let number of bowls be x
\n" ); document.write( "and plates be y\r
\n" ); document.write( "\n" ); document.write( "time taken
\n" ); document.write( "3x+2y= 480 \r
\n" ); document.write( "\n" ); document.write( "Money spent
\n" ); document.write( "0.25x+0.2y = 44
\n" ); document.write( "multiply by 100 to eliminate the decimals
\n" ); document.write( "25x+20y=4400\r
\n" ); document.write( "\n" ); document.write( "bowls x numbers , Price = $3.00
\n" ); document.write( "plates y numbers , Price = $9.00
\n" ); document.write( " Total 345
\n" ); document.write( "3 x + 2 y = 480 .............1
\n" ); document.write( "25 x + 20 y = 4400 .............2
\n" ); document.write( "Eliminate y
\n" ); document.write( "multiply (1)by -10
\n" ); document.write( "Multiply (2) by 1
\n" ); document.write( "-30 x -20 y = -4800
\n" ); document.write( "25 x 20 y = 4400
\n" ); document.write( "Add the two equations
\n" ); document.write( "-5 x = -400
\n" ); document.write( "/ -5
\n" ); document.write( "x = 80
\n" ); document.write( "plug value of x in (1)
\n" ); document.write( "3 x + 2 y = 480
\n" ); document.write( "240 + 2 y = 480
\n" ); document.write( " 2 y = 480 -240
\n" ); document.write( " 2 y = 240
\n" ); document.write( " y = 120
\n" ); document.write( "bowls 80 numbers
\n" ); document.write( "plates 120 numbers
\n" ); document.write( "m.ananth@hotmail.ca
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