document.write( "Question 534358: How do I use two variables and two equations to solve this problem. A machine in a
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document.write( "pottery factory takes 3 minutes to form a bowl and 2 minutes to form a plate. The material for a bowl costs $0.25, and the material for a plate costs $0.20. If the machine runs for 8 hours and exactly $44 is spent for material, how many bowls and plates can be produced? How do I set it up? \n" );
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Algebra.Com's Answer #351561 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let number of bowls be x \n" ); document.write( "and plates be y\r \n" ); document.write( "\n" ); document.write( "time taken \n" ); document.write( "3x+2y= 480 \r \n" ); document.write( "\n" ); document.write( "Money spent \n" ); document.write( "0.25x+0.2y = 44 \n" ); document.write( "multiply by 100 to eliminate the decimals \n" ); document.write( "25x+20y=4400\r \n" ); document.write( "\n" ); document.write( "bowls x numbers , Price = $3.00 \n" ); document.write( "plates y numbers , Price = $9.00 \n" ); document.write( " Total 345 \n" ); document.write( "3 x + 2 y = 480 .............1 \n" ); document.write( "25 x + 20 y = 4400 .............2 \n" ); document.write( "Eliminate y \n" ); document.write( "multiply (1)by -10 \n" ); document.write( "Multiply (2) by 1 \n" ); document.write( "-30 x -20 y = -4800 \n" ); document.write( "25 x 20 y = 4400 \n" ); document.write( "Add the two equations \n" ); document.write( "-5 x = -400 \n" ); document.write( "/ -5 \n" ); document.write( "x = 80 \n" ); document.write( "plug value of x in (1) \n" ); document.write( "3 x + 2 y = 480 \n" ); document.write( "240 + 2 y = 480 \n" ); document.write( " 2 y = 480 -240 \n" ); document.write( " 2 y = 240 \n" ); document.write( " y = 120 \n" ); document.write( "bowls 80 numbers \n" ); document.write( "plates 120 numbers \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " \n" ); document.write( " |