document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=533776>Question 533776</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If 42 ounces of red beads that sell for $7 per ounce are mixed with 58 ounces of golden beads that sell for $10 per ounce, what should be the selling price for the mixture of beads? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #351541 by </B><A HREF=/tutors/aboutme.mpl?userid=Maths68><B>Maths68(1474)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Maths68><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Maths68><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=351541\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  \r<BR>\n" );
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document.write( "Red Beads = 42 oz<BR>\n" );
document.write( "Price = $7/oz<BR>\n" );
document.write( "Golden Beads = 58 oz<BR>\n" );
document.write( "Price = 10/oz<BR>\n" );
document.write( "Mixture = (42+58)oz=100oz<BR>\n" );
document.write( "Pirce = x = $?/oz\r<BR>\n" );
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document.write( "(Mixture)(Price of mixture)=(Red Beads)(Price of Red Beads)+(Golden Beads)(Price of Golden Beads) \r<BR>\n" );
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document.write( "(100)x=(42*7)+(58*10)<BR>\n" );
document.write( "100x=294+580<BR>\n" );
document.write( "100x=874<BR>\n" );
document.write( "x=874/100<BR>\n" );
document.write( "x=8.74\r<BR>\n" );
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document.write( "$8.74 per ounce should be the selling price for the mixture of beads. </SPAN>\n" );
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