document.write( "Question 533630: Mary is three years younger than three times Emily's age. The sum of their ages is 53. Find their ages. \n" ); document.write( "
Algebra.Com's Answer #351539 by Maths68(1474)\"\" \"About 
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Let
\n" ); document.write( "Present age of Mary = m
\n" ); document.write( "Present age of Emily = e\r
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\n" ); document.write( "\n" ); document.write( "Mary is three years younger than three times Emily's age
\n" ); document.write( "m=3e-3............(1)
\n" ); document.write( "The sum of their ages is 53
\n" ); document.write( "m+e=53.............(2)
\n" ); document.write( "Put the value of m from (1) to (2)
\n" ); document.write( "(3e-3)+e=53
\n" ); document.write( "3e-3+e=53
\n" ); document.write( "4e=53+3
\n" ); document.write( "4e=56
\n" ); document.write( "e=56/4
\n" ); document.write( "e=14
\n" ); document.write( "Put the value of e in (1)
\n" ); document.write( "m=3e-3
\n" ); document.write( "m=3(14)-3
\n" ); document.write( "m=42-3
\n" ); document.write( "m=39\r
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\n" ); document.write( "\n" ); document.write( "Present age of Mary = m = 39
\n" ); document.write( "Present age of Emily = e = 14
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