document.write( "Question 534386: A car travels 125 miles in the same time an airplane travels 1515 miles. If the rate of the car is 315 miles per hour less than the rate of the airplane, what is the rate of each? Let r represent the rate of the car. Note: Because the time of travel for the car is equal to the time of travel for the plane we can compare the distance and rate (distance = rate x time). \n" ); document.write( "
Algebra.Com's Answer #351520 by josmiceli(19441)\"\" \"About 
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Let \"t\" = the time for each
\n" ); document.write( "Let \"s\" = the speed of the plane
\n" ); document.write( "Car:
\n" ); document.write( "(1) \"+125+=+%28+s+-+315+%29%2At+\"
\n" ); document.write( "Plane:
\n" ); document.write( "(2) \"+1515+=+s%2At+\"
\n" ); document.write( "--------------
\n" ); document.write( "(2) \"+t+=+1515%2Fs+\"
\n" ); document.write( "Substitute (2) into (1)
\n" ); document.write( "(1) \"+125+=+%28+s+-+315+%29%2A%281515%2Fs%29+\"
\n" ); document.write( "(1) \"+125+=+1515+-+477225%2Fs+\"
\n" ); document.write( "(1) \"+125s+=+1515s+-+477225+\"
\n" ); document.write( "(1) \"+1390s+=+477225+\"
\n" ); document.write( "(1) \"+s+=+343.327+\" mi/hr
\n" ); document.write( "\"+s+-+315+=+343.327+-+315+\"
\n" ); document.write( "\"+s+-+315+=+28.327+\" mi/hr
\n" ); document.write( "The speed of the car is 28.327 mi/hr
\n" ); document.write( "The speed of the plane is 343.327 mi/hr
\n" ); document.write( "------------------
\n" ); document.write( "check:
\n" ); document.write( "(2) \"+t+=+1515%2F343.327+\"
\n" ); document.write( "(2) \"+t+=+4.413+\" hrs
\n" ); document.write( "and
\n" ); document.write( "(1) \"+125+=+%28+343.327+-+315+%29%2A4.413+\"
\n" ); document.write( "(1) \"+125+=+28.327%2A4.413+\"
\n" ); document.write( "(1) \"+125+=+125.007+\"
\n" ); document.write( "Seems close enough
\n" ); document.write( "
\n" );