document.write( "Question 534333: Given the equation (x-3)^2 + (y+2)^2 = 9, (a)find the center and radius; (b)graph; (c)find the intercepts, if any. Please help! I am completely confused. \n" ); document.write( "
Algebra.Com's Answer #351486 by Earlsdon(6294)\"\" \"About 
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Compare the given equation
\n" ); document.write( "\"%28x-3%29%5E2%2B%28y%2B2%29%5E2+=+9\" with
\n" ); document.write( "\"%28x-h%29%5E2%2B%28y-k%29%5E2+=+r%5E2\"} This is the general form of the equation of a circle with its center at (h,k) and a radius of r.
\n" ); document.write( "So you can easily identify the center and radius of the given equation as:
\n" ); document.write( "Center at (3, -2) and radius of 3.
\n" ); document.write( "To graph the equation, you must first solve the equation for y:
\n" ); document.write( "\"%28x-3%29%5E2%2B%28y%2B2%29%5E2+=+9\" Subtract \"%28x-3%29%5E2\" from both sides.
\n" ); document.write( "\"%28y%2B2%29%5E2+=+9-%28x-3%29%5E2\" Take the square root of both sides.
\n" ); document.write( "\"y%2B2+=+sqrt%289-%28x-3%29%5E2%29\" Subtract 2 from both sides.
\n" ); document.write( "\"y+=+sqrt%289-%28x-3%29%5E2%29-2\" and \"y+=+-sqrt%289-%28x-3%29%5E2%29-2\" Now graph these two equations.
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