document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=534270>Question 534270</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A merchant has coffee worth $60 a pound that she wishes to miz with 70 pounds of coffee worth $90 a pound to get a mixture that is worth $70 a pound. How many pounds of the $60 coffee should be used? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #351444 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=351444\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A merchant has coffee worth $60 a pound that she wishes to miz with 70 pounds of coffee worth $90 a pound to get a mixture that is worth $70 a pound. How many pounds of the $60 coffee should be used?<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "value + value = value<BR>\n" );
document.write( "60x + 90*70 = 70*(x+70)<BR>\n" );
document.write( "60x + 90*70 = 70x + 70*70<BR>\n" );
document.write( "-10x = -20*70<BR>\n" );
document.write( "x = 140 (amt. of $60 coffee needed)<BR>\n" );
document.write( "===========<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );