document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=532962>Question 532962</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Approximate the value of log(base2)10 to 3 decimal places. \r<BR>\n" );
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document.write( "*Convert to a convenient base and evaluate on the calculator.\r<BR>\n" );
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document.write( "I have no idea what to do lol  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #351431 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=351431\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Approximate the value of log(base2)10 to 3 decimal places. <BR>\n" );
document.write( "Convert to a convenient base and evaluate on the calculator.<BR>\n" );
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document.write( "Remember the definition of a logarithm?: base raised to logarithm of the number is equal to the number<BR>\n" );
document.write( "In this case: <BR>\n" );
document.write( "base=2<BR>\n" );
document.write( "number=10<BR>\n" );
document.write( "logarithm of the number=x (what you must find)<BR>\n" );
document.write( "so now you have this equation: <BR>\n" );
document.write( "2^x=10<BR>\n" );
document.write( "If you have a calculator it is a simple matter to find x by using the log function which is base (10)<BR>\n" );
document.write( "taking the log of both sides:<BR>\n" );
document.write( "xlog2=log10=1 (log of the base is always=1)<BR>\n" );
document.write( "x=1/log2<BR>\n" );
document.write( "x&#8776;3.322<BR>\n" );
document.write( "What this says is that if you  raise 2 to 3.322 you will &#8776; 10. </SPAN>\n" );
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