document.write( "Question 534178: find all the solutions on the interval [0,2pi)
\n" ); document.write( "tan^2x-4tanx+3=0
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Algebra.Com's Answer #351408 by lwsshak3(11628)\"\" \"About 
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find all the solutions on the interval [0,2pi)
\n" ); document.write( "tan^2x-4tanx+3=0
\n" ); document.write( "factor:
\n" ); document.write( "(tanx-3)(tanx-1)=0
\n" ); document.write( "tanx-3=0
\n" ); document.write( "tanx=3
\n" ); document.write( "using calculator:
\n" ); document.write( "x=arctan(3)≈1.25 and 4.57 radians (in quadrants I and III where tan>0)
\n" ); document.write( "..
\n" ); document.write( "tanx-1=0
\n" ); document.write( "tanx=1
\n" ); document.write( "x=arctan(1)=π/4 and 5π/4 radians (in quadrants I and III where tan>0)
\n" ); document.write( "solutions:1.25, 4.57, π/4 and 5π/4 radians
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