document.write( "Question 534212: the sum of three numbers is 50. one number is ten more then the second number. it is also twice the third number. find the numbers \n" ); document.write( "

Algebra.Com's Answer #351389 by Maths68(1474) $\"\"$ $\"About$

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Let
\n" ); document.write( "One number = x
\n" ); document.write( "Second number =x-10
\n" ); document.write( "Third number = x/2\r
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\n" ); document.write( "\n" ); document.write( "Sum of three numbers is 50\r
\n" ); document.write( "\n" ); document.write( "x+x-10+x/2=50
\n" ); document.write( "2x-10+x/2=50
\n" ); document.write( "Multiply by 2 both sides
\n" ); document.write( "2*(2x-10+x/2)=50*2
\n" ); document.write( "4x-20+x=100
\n" ); document.write( "5x=100+20
\n" ); document.write( "5x=120
\n" ); document.write( "x=120/5
\n" ); document.write( "x=24\r
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\n" ); document.write( "\n" ); document.write( "One number = x = 24
\n" ); document.write( "Second number =x-10 = 24-10 = 14
\n" ); document.write( "Third number = x/2 = 24/2 = 12\r
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