document.write( "Question 534174: How would. You simplify this problem?\r
\n" ); document.write( "\n" ); document.write( "\"%287-6i%29%2B%289%2B11i%29\"\r
\n" ); document.write( "\n" ); document.write( "I added 6i to both sides and got 17i then I brought the 9 and 7 down to get 7+9+17. Then added all three numbers together and got 33. I'm not sure if this is correct
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Algebra.Com's Answer #351369 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
I'm confused. Maybe something got mixed up in the text of the problem or the previous answer.
\n" ); document.write( "Were you supposed to add the two complex numbers or multiply them?
\n" ); document.write( "If adding
\n" ); document.write( "\"%287-6i%29%2B%289%2B11i%29=%287%2B9%29%2Bi%28-6%2B11%29=16%2B5i\"
\n" ); document.write( "When working with complex numbers, you work as if the i was a variable x.
\n" ); document.write( "You cannot mix the real part of the number, with the imaginary part that has the i, just like you cannot add 16+5x.
\n" ); document.write( "The only difference is that the even powers of i are real numbers, so multiplications of complex numbers can always simplify to something as short as \"16%2B5i\"
\n" ); document.write( "\"i%5E2=-1\", \"i%5E4=1\" and all \"i%5Eevennumber\" powers simplify to \"1\" (if the exponent is a multiple of 4) or to \"-1\" (if not a multiple of 4).
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