document.write( "Question 512216: Please help me with these:\r
\n" ); document.write( "\n" ); document.write( "1. If 7 men can do 3 jobs in 27 hours then ? men can do 5 jobs in 35 hours.\r
\n" ); document.write( "\n" ); document.write( "2. If 10 men can do 6 jobs in 48 hours then 6 men can do ? jobs in 40 hours.\r
\n" ); document.write( "\n" ); document.write( "3. If 8 men can do 5 jobs in 10 hours then 5 men can do 10 jobs in ? hours.\r
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Algebra.Com's Answer #351366 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "1.  If 7 men can do 3 jobs in 27 hours then ? men can do 5 jobs in 35 hours.\r\n" );
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document.write( "The easiest way to do these problems is to use the fact that\r\n" );
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document.write( "k = (Number of workers) × (Number of hours*) ÷ (Number of jobs)\r\n" );
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document.write( "*(or minutes or days in some problems)\r\n" );
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document.write( "where k is a constant for any number of workers, hours or jobs,\r\n" );
document.write( "So we calculate the constant k from the first situation:\r\n" );
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document.write( "7 men can do 3 jobs in 27 hours\r\n" );
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document.write( "7×27÷3 = 63\r\n" );
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document.write( "Then we let the answer to the problem be 'N men', and we have\r\n" );
document.write( "for the second situation:\r\n" );
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document.write( "N men can do 5 jobs in 35 hours\r\n" );
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document.write( "So\r\n" );
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document.write( "N×35÷5 must equal the constant k = 63\r\n" );
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document.write( "N×35÷5 = 63\r\n" );
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document.write( "   N×7 = 63 \r\n" );
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document.write( "     N = 63÷7\r\n" );
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document.write( "     N = 9\r\n" );
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document.write( "It would take 9 men.\r\n" );
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document.write( "Edwin
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