document.write( "Question 534134: on a plane, two men together had 135 kilograms of luggage.The first paid $1.35 for his excess luggage and the second paid S2.70 for his excess luggage. had all the luggage belonged to one person, the excess luggage charge would have been $8.10. At most how many kilograms of luggage is each person permitted to bring on the plane free of additional charge. \n" ); document.write( "
Algebra.Com's Answer #351344 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let x kg be the free allowance\r \n" ); document.write( "\n" ); document.write( "for both of them the free allowance = 2x \n" ); document.write( "135-2x is the excess luggage\r \n" ); document.write( "\n" ); document.write( "135-2x they paid $4.05\r \n" ); document.write( "\n" ); document.write( "1 kg they pay how much ?\r \n" ); document.write( "\n" ); document.write( "They pay 4.05/(135-2x) per kg excess\r \n" ); document.write( "\n" ); document.write( "Single person\r \n" ); document.write( "\n" ); document.write( "135-x is the excess luggage\r \n" ); document.write( "\n" ); document.write( "For 135 kg he pays $8.10\r \n" ); document.write( "\n" ); document.write( "He pays 8.10/(135-x)per kg for excess luggage\r \n" ); document.write( "\n" ); document.write( "The rate per kg for excess luggage is the same so equate both\r \n" ); document.write( "\n" ); document.write( "4.05/(135-2x)=8.10/(135-x)\r \n" ); document.write( "\n" ); document.write( "4.05(135-x)=8.10(135-2x)\r \n" ); document.write( "\n" ); document.write( "546.75-4.05x=1093.5-16.2x\r \n" ); document.write( "\n" ); document.write( "12.15x=546.75 \n" ); document.write( "/12.15 \n" ); document.write( "x=45 kg free luggage allowance\r \n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |