document.write( "Question 534061: A clothing company borrows $775,000. Some of the money is borrowed at 8%, some at 9%, and some at 10% simple annual interest. How much is borrowed at each rate if the total annual interest is $67,500 and the amount borrowed at 8% is four times the amount borrowed at 10%? \n" ); document.write( "
Algebra.Com's Answer #351316 by mananth(16946)\"\" \"About 
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8%--------------------x
\n" ); document.write( "9%--------------------y\r
\n" ); document.write( "\n" ); document.write( "10%-------------------z\r
\n" ); document.write( "\n" ); document.write( "x=4z\r
\n" ); document.write( "\n" ); document.write( "therefore 8% -----------4z\r
\n" ); document.write( "\n" ); document.write( "4z+y+z=775000
\n" ); document.write( "5z+y=775000...................(1)\r
\n" ); document.write( "\n" ); document.write( "0.08*4z+0.09y+0.1z=67500
\n" ); document.write( "0.32z+0.09y+0.1z=67500
\n" ); document.write( "0.42z+0.09y=67500.............(2)\r
\n" ); document.write( "\n" ); document.write( "5 z + 1 y = 775000 .............1
\n" ); document.write( "0.42 z + 0.09 y = 67500 .............2
\n" ); document.write( "Eliminate y
\n" ); document.write( "multiply (1)by -0.09
\n" ); document.write( "Multiply (2) by 1
\n" ); document.write( "-0.45 z -0.09 y = -69750
\n" ); document.write( "0.42 z 0.09 y = 67500
\n" ); document.write( "Add the two equations
\n" ); document.write( "-0.03 z = -2250
\n" ); document.write( "/ -0.03
\n" ); document.write( "z = 75,000.00
\n" ); document.write( "plug value of z in (1)
\n" ); document.write( "5 z + 1 y = 775000
\n" ); document.write( "375000 + 1 y = 775000
\n" ); document.write( " 1 y = 775000 -375000
\n" ); document.write( " 1 y = 400000
\n" ); document.write( " y = 400000.00
\n" ); document.write( "10% ------------$75000
\n" ); document.write( "9%--------------$400000
\n" ); document.write( "8%--------------4*75000= $300000\r
\n" ); document.write( "\n" ); document.write( "CHECK\r
\n" ); document.write( "\n" ); document.write( "75000*0.1+400000*0.09+300000*0.08=67500\r
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\n" ); document.write( "m.ananth@hotmail.ca \r
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