document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=534101>Question 534101</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Tow buses leave towns 345 miles apart at the same time and travel toward each other. One bus travels nine miles an hour slower than the other. if they meet in 3 hours, what is the rate of each bus? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #351304 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=351304\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Tow buses leave towns 345 miles apart at the same time and travel toward each other. One bus travels nine miles an hour slower than the other. if they meet in 3 hours, what is the rate of each bus?<BR>\n" );
document.write( "**<BR>\n" );
document.write( "let x= rate of faster bus in mph<BR>\n" );
document.write( "x-9= rate of slower bus in mph<BR>\n" );
document.write( "distance=rate*travel time<BR>\n" );
document.write( "..<BR>\n" );
document.write( "3x+3(x-9)=345<BR>\n" );
document.write( "3x+3x-27=345<BR>\n" );
document.write( "6x=372<BR>\n" );
document.write( "x=62 mph<BR>\n" );
document.write( "x-9=53 mph<BR>\n" );
document.write( "ans:<BR>\n" );
document.write( "rate of faster bus=62 mph<BR>\n" );
document.write( "rate of slower bus=53 mph </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );