document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=534044>Question 534044</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The product of second and third  of 3 consecutive integers is 3 more than 3 times the second integer. find the 3 integers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #351274 by </B><A HREF=/tutors/aboutme.mpl?userid=MathTherapy><B>MathTherapy(10557)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathTherapy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathTherapy><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=351274\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The product of second and third  of 3 consecutive integers is 3 more than 3 times the second integer. find the 3 integers\r<BR>\n" );
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document.write( "Let the 1st integer be F\r<BR>\n" );
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document.write( "Then the other 2 are:  F + 1, and F + 2\r<BR>\n" );
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document.write( "We have: (F + 1)(F + 2) = 3(F + 1) + 3\r<BR>\n" );
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document.write( "F, or 1st integer = ± 2\r<BR>\n" );
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document.write( "Therefore, the consecutive integers are either:<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%282_3_and_4%29 ALIGN=MIDDLE  ALT=\"highlight_green%282_3_and_4%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >, or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%28-2_-1_and_0%29 ALIGN=MIDDLE  ALT=\"highlight_green%28-2_-1_and_0%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Integers are: 2, 3, & 4<BR>\n" );
document.write( "Product of 2nd and 3rd: (3 * 4) = 3(3) + 3 ---- 12 = 9 + 3 ---- 12 = 12 (TRUE)\r<BR>\n" );
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document.write( "Integers are: - 2, - 1, & 0<BR>\n" );
document.write( "Product of 2nd and 3rd: (- 1 * 0) = 3(- 1) + 3 ---- 0 = - 3 + 3 ---- 0 = 0 (TRUE)\r<BR>\n" );
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document.write( "Send comments and “thank-yous” to “D” at  MathMadEzy@aol.com </SPAN>\n" );
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